Question

А) 3y(7+y)= б) 5x²-3x(x+2)

Answer 1

а) 3у ( 7 + у ) = 21у + 3у².

б) 5х² - 3х ( х + 2 ) = 5х² - 3х² - 6х = 2х² - 6х.

Удачи))))

Answer 2

3y (7+y)=21y+3y^2
5x-3x (x+2)
5x-3x^2-6x
-3x^2 - x |:(-1)
3 x^2+x

Answer 3

Let's solve both equations step by step:

А) 3y(7 + y) = 0

To solve this equation, we need to find the values of y that make the equation true. To do that, we can set each factor to zero and solve for y:

1. Set 3y = 0: y = 0

2. Set 7 + y = 0: y = -7

So, the solutions for the equation are y = 0 and y = -7.

Б) 5x² - 3x(x + 2) = 0

To solve this equation, we first need to simplify the expression on the left-hand side:

5x² - 3x(x + 2) = 5x² - 3x² - 6x

Now, combine like terms:

5x² - 3x² - 6x = 2x² - 6x

Now, we set this expression equal to zero and solve for x:

2x² - 6x = 0

Factor out the common factor (2x):

2x(x - 3) = 0

Now, we set each factor to zero and solve for x:

1. Set 2x = 0: x = 0

2. Set x - 3 = 0: x = 3

So, the solutions for the equation are x = 0 and x = 3.

To summarize:

А) The solutions for the equation 3y(7 + y) = 0 are y = 0 and y = -7.

Б) The solutions for the equation 5x² - 3x(x + 2) = 0 are x = 0 and x = 3.