Question

4(4x−10)^2−8(4x−10)+4=0

Answer 1

Сори, что так грязно

Answer 2

4(4x−10)^2−8(4x−10)+4=0

4(4x-10)(4x-10-2+1)=0

4(4x-10)(4x-11)=0

4≠0

4x-10=0

x1=10/4=2.5

4x-11=0

x2=11/4

ответ:x1=2.5  , x2=11/4

Answer 3

To solve the quadratic equation 4(4x - 10)^2 - 8(4x - 10) + 4 = 0, we can use a substitution to simplify it. Let's set y = 4x - 10:

Now, our equation becomes: 4y^2 - 8y + 4 = 0.

Next, we can divide the entire equation by 4 to simplify it further: y^2 - 2y + 1 = 0.

This is a simple quadratic equation that can be factored easily: (y - 1)^2 = 0.

Now, we'll solve for y:

y - 1 = 0

y = 1.

Now, remember that y = 4x - 10. We already know y is equal to 1, so we can solve for x:

4x - 10 = 1

Add 10 to both sides:

4x = 11

Divide by 4:

x = 11/4.

So the solution to the quadratic equation is x = 11/4 or 2.75.