Question

3·(х-2)+х=-(-4х+16)+10

Answer 1

3·(х-2)+х=-(-4х+16)+10
3x-6+x=4x-16+10
4x-6=4x-6
Утверждение верно.

Answer 2

Let's solve the given equation step by step:

3·(х-2) + х = -(-4х+16) + 10

First, let's simplify both sides of the equation:

3·х - 3·2 + х = 4х - 16 + 10

Now, combine like terms on both sides:

4х - 6 = 4х - 6

Notice that we have the same term (4х - 6) on both sides of the equation, which means the equation is an identity. This means that the equation is true for any value of x.

The solution to this equation is "All real numbers". In other words, for any value of x you choose, the equation will hold true.