Question

6/x+2+4/x-2=1 срооооочно​

Answer 1

Ответ:

6/x+2+4/x-2=1

6/x+4/x=10/x=1

x=10/1

x=10

Объяснение:

2 и -2 складываем получается 0

Answer 2

Надеюсь помогла))))))

Answer 3

To solve the equation $\frac{6}{x+2} + \frac{4}{x-2} = 1$, we need to find the value(s) of $x$ that satisfy the equation. Let's proceed with the solution step-by-step:

Step 1: Find a common denominator for the fractions on the left side of the equation.

The common denominator for $x+2$ and $x-2$ is $(x+2)(x-2)$. Rewrite the equation with the common denominator:

$\frac{6(x-2)}{(x+2)(x-2)} + \frac{4(x+2)}{(x+2)(x-2)} = 1$

Step 2: Combine the fractions on the left side of the equation:

$\frac{6(x-2) + 4(x+2)}{(x+2)(x-2)} = 1$

Step 3: Distribute and simplify the expressions in the numerator:

$\frac{6x - 12 + 4x + 8}{(x+2)(x-2)} = 1$

$\frac{10x - 4}{(x+2)(x-2)} = 1$

Step 4: Eliminate the fraction by multiplying both sides of the equation by $(x+2)(x-2)$:

$(x+2)(x-2) \times \frac{10x - 4}{(x+2)(x-2)} = 1 \times (x+2)(x-2)$

$10x - 4 = (x+2)(x-2)$

Step 5: Expand the right side of the equation:

$10x - 4 = x^2 - 2x + 2x - 4$

Step 6: Move all terms to one side to set the equation to zero:

$x^2 - 10x + 4 - 2x + 4 = 0$

$x^2 - 12x + 8 = 0$

Step 7: Now, we have a quadratic equation. We can solve it using the quadratic formula:

The quadratic formula is given by $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In our case, $a = 1$, $b = -12$, and $c = 8$.

$x = \frac{-(-12) \pm \sqrt{(-12)^2 - 4 \times 1 \times 8}}{2 \times 1}$

$x = \frac{12 \pm \sqrt{144 - 32}}{2}$

$x = \frac{12 \pm \sqrt{112}}{2}$

$x = \frac{12 \pm 4\sqrt{7}}{2}$

Step 8: Simplify further:

$x = 6 \pm 2\sqrt{7}$

So, the two solutions for the equation are $x = 6 + 2\sqrt{7}$ and $x = 6 - 2\sqrt{7}$.