Question

12х+12у/36х^2-36у^2 сократить дробь

Answer 1

$\frac{12x+12y}{36x^{2}-36y^{2}}=\frac{12(x+y)}{36(x+y)(x-y)}=\frac{1}{3(x-y)}=\frac{1}{3x-3y}$

Answer 2

To simplify the expression (12x + 12y) / (36x^2 - 36y^2), we can first factor the numerator and the denominator:

Numerator (12x + 12y): Factor out 12: 12(x + y)

Denominator (36x^2 - 36y^2): Factor out 36: 36(x^2 - y^2)

Now, the expression becomes:

(12(x + y)) / (36(x^2 - y^2))

Next, we can simplify further. Notice that (x^2 - y^2) is a difference of squares, which can be factored as (x + y)(x - y). So, we can rewrite the expression as follows:

(12(x + y)) / (36(x + y)(x - y))

Now, we can cancel out the common factor of (x + y) in the numerator and the denominator:

(12 * 1) / (36 * (x - y))

Finally, simplify the fraction:

12 / (36 * (x - y))

Now, we can reduce the fraction by dividing the numerator and denominator by their greatest common divisor (GCD), which is 12:

12 ÷ 12 = 1 36 ÷ 12 = 3

The simplified expression is:

1 / (3 * (x - y))