Question

(x^2-7)^4=16 Срочно

Answer 1

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Готово!!!Удачи))))

Answer 2

To solve the equation $(x^2 - 7)^4 = 16$, follow these steps:

Step 1: Take the fourth root of both sides of the equation to remove the fourth power.

$\sqrt[4]{(x^2 - 7)^4} = \sqrt[4]{16}$

Step 2: Simplify the equation on both sides.

$x^2 - 7 = \sqrt[4]{16}$

Step 3: Evaluate $\sqrt[4]{16}$:

$\sqrt[4]{16} = \sqrt[4]{2^4} = 2$

Step 4: Substitute the value of $\sqrt[4]{16}$ back into the equation:

$x^2 - 7 = 2$

Step 5: Add 7 to both sides of the equation to isolate $x^2$ on one side.

$x^2 = 2 + 7$

Step 6: Simplify the right-hand side.

$x^2 = 9$

Step 7: Take the square root of both sides to solve for $x$.

$x = \pm \sqrt{9}$

Step 8: Simplify the square root of 9.

$x = \pm 3$

So, the solutions to the equation are $x = 3$ and $x = -3$.