Question

(1-a²):((1-√a³/1-√a+√a).(1+√a³/1+√a-√a))+1​

Answer 1

Объяснение:

(1-а^2)÷(1-√а^3/1-0)(1+√а^3/1+0)+1=(1-а^2)÷(1-√а^3)(1+√а^3)+1=(1-а^2)÷(1^2 -(√а^3)^2)+1=(1-а^2)÷(1-а^3)+1=(1-а^2)/(1-а^3) +(1-а^3)/(1-а^3)=(1-а^2+1-а^3)/(1-а^3)=(2-а^2(1-а)/(1-а^3)

Answer 2

To simplify the given expression, let's start by breaking down the terms step by step:

1. Rewrite the expression with square roots: (1 - a²) / ((1 - √a³) / (1 - √a + √a)) * ((1 + √a³) / (1 + √a - √a)) + 1

2. Simplify the inner fractions: (1 - a²) / (1 - √a³ + √a) * (1 + √a³) / (1 - √a + √a) + 1

3. Simplify the denominator in the first fraction and the numerator in the second fraction: (1 - a²) / (-√a³ + √a) * (1 + √a³) / 1 + 1

4. Now, simplify the fraction by combining the terms in the numerator and denominator: (1 - a²) / (√a - √a³) * (1 + √a³) / 1 + 1

5. Remove the unnecessary parentheses since there are no terms to distribute: (1 - a²) / (√a - √a³) * (1 + √a³) / 1 + 1

6. The last step is to simplify further: (1 - a²) * (1 + √a³) / (√a - √a³) + 1

Now, the expression is simplified to:

(1 - a²) * (1 + √a³) / (√a - √a³) + 1