Question

3х^2-2(х^2-2х)+2х-11=5

Answer 1

Решение задания приложено

Answer 2

Let's solve the given equation step by step:

1. Combine like terms on the left-hand side (LHS):

3x^2 - 2(x^2 - 2x) + 2x - 11 = 5

First, distribute the -2 through the parentheses:

3x^2 - 2x^2 + 4x + 2x - 11 = 5

Combine the like terms:

(3x^2 - 2x^2) + (4x + 2x) - 11 = 5

Simplify:

x^2 + 6x - 11 = 5

2. Move all terms to one side of the equation to set it to zero:

x^2 + 6x - 11 - 5 = 0

x^2 + 6x - 16 = 0

3. To solve the quadratic equation, we can use the quadratic formula:

For a quadratic equation of the form ax^2 + bx + c = 0, the quadratic formula is:

x = (-b ± √(b^2 - 4ac)) / 2a

In our case, a = 1, b = 6, and c = -16:

x = (-(6) ± √(6^2 - 4 * 1 * -16)) / 2 * 1

x = (-6 ± √(36 + 64)) / 2

x = (-6 ± √100) / 2

x = (-6 ± 10) / 2

Now, we have two possible solutions for x:

1. x = (-6 + 10) / 2 x = 4 / 2 x = 2

2. x = (-6 - 10) / 2 x = -16 / 2 x = -8

So, the solutions to the equation are x = 2 and x = -8.