Question

(х+х-4)*2=28; (3х+х)*2=24.​

Answer 1

$(x + x - 4) \times 2 = 28 \\ 2 \times x - 4 = 28 \div 2 \\ 2 \times x - 4 = 14 \\ 2 \times x = 14 + 4 \\ 2 \times x = 18 \\ x = 18 \div 2 \\ x = 9$

$(3x + x) \times 2 = 24 \\ (3x + x) = 24 \div 2 \\ 4 \times x = 12 \\ x = 12 \div 4 \\ x = 3$

Answer 2

Let's solve the given equations step by step:

Equation 1: (2x + x - 4) * 2 = 28

First, simplify the expression inside the parentheses:

2x + x - 4 = 28 / 2 3x - 4 = 14 3x = 14 + 4 3x = 18

Now, divide both sides of the equation by 3 to solve for x:

x = 18 / 3 x = 6

So, the solution for Equation 1 is x = 6.

Equation 2: (3x + x) * 2 = 24

Simplify the expression inside the parentheses:

4x * 2 = 24 8x = 24

Now, divide both sides of the equation by 8 to solve for x:

x = 24 / 8 x = 3

Therefore, the solution for Equation 2 is x = 3.

In summary: Equation 1: x = 6 Equation 2: x = 3