Question

(2x-1)•(3x+5)-(2x-1)•5x+7(2x-1)=0​

Answer 1

Ответ:

1

Объяснение:

(2x-1)•(3x+5)-(2x-1)•5x+7(2x-1)=0​

6х-3х+10х-5-10х-5+14х-7=0

17х-17=0

17х=17

х=17/17

х=1

Answer 2

Let's solve the given equation step by step:

(2x - 1) * (3x + 5) - (2x - 1) * 5x + 7(2x - 1) = 0

First, let's simplify the expression:

Expanding the first two terms using the distributive property:

(2x * 3x + 2x * 5 - 1 * 3x - 1 * 5) - (2x * 5x - 1 * 5x) + (7 * 2x - 7 * 1) = 0

Simplifying each term:

(6x^2 + 10x - 3x + 5) - (10x^2 - 5x) + (14x - 7) = 0

Combine like terms:

6x^2 + 10x - 3x + 5 - 10x^2 + 5x + 14x - 7 = 0

Simplify further:

(6x^2 - 10x^2) + (10x - 3x + 5x + 14x) + (5 - 7) = 0

-4x^2 + 26x - 2 = 0

Now, we have a quadratic equation in the form ax^2 + bx + c = 0, where a = -4, b = 26, and c = -2. To solve this equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Substituting the values, we get:

x = (-(26) ± √((26)^2 - 4(-4)(-2))) / (2(-4))

Simplifying:

x = (-26 ± √(676 - 32)) / (-8)

x = (-26 ± √(644)) / (-8)

x = (-26 ± √(4 * 161)) / (-8)

x = (-26 ± 2√161) / (-8)

Simplifying further:

x = (26 ± 2√161) / 8

x = (13 ± √161) / 4

Therefore, the solutions to the equation (2x - 1) * (3x + 5) - (2x - 1) * 5x + 7(2x - 1) = 0 are:

x = (13 + √161) / 4 x = (13 - √161) / 4