Question

4x²+4x+1=0 Решите уравнение

Answer 1

Ответ:

4x²-4x+1=0

D=(-4)^2-4*4*1=16-16=0

x1,2=4/8=1/2=0,5

Answer 2

Ответ:

0,5

Объяснение:

4x²-4x+1=0

(-4)^2-4*4*1=16-16=0

x1,2=4/8=1/2=0,5

Answer 3

To solve the quadratic equation 4x² + 4x + 1 = 0, we can use the quadratic formula, which is given by:

x = (-b ± √(b² - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation in the form ax² + bx + c = 0.

For the given equation: 4x² + 4x + 1 = 0, we have:

a = 4 b = 4 c = 1

Now, plug these values into the quadratic formula and solve for x:

x = (-(4) ± √((4)² - 4(4)(1))) / 2(4) x = (-4 ± √(16 - 16)) / 8 x = (-4 ± √0) / 8 x = (-4 ± 0) / 8

We have a discriminant (the term inside the square root) of 0, which means there is only one real solution for x:

x = (-4 + 0) / 8 x = -4 / 8 x = -1/2

So, the solution to the equation 4x² + 4x + 1 = 0 is x = -1/2.