Question

Cos(225°-150°)вычислить. Sin(225°-150°)

Answer 1

cos(225°-150°)=cos(75°)=cos(30°+45°)=cos(30°)cos(45°)-sin(30°)sin(45°)=$\frac{\sqrt{3} }{2}*\frac{\sqrt{2} }{2}-\frac{1}{2} *\frac{\sqrt{2} }{2} =\frac{\sqrt{6} -\sqrt{2} }{4}$

sin(225°-150°)=sin(75°)=sin(30°+45°)=sin(30°)cos(45°)+cos(30°)sin(45°)=$\frac{1}{2}*\frac{\sqrt{2} }{2} + \frac{\sqrt{3} }{2}*\frac{\sqrt{2} }{2}=\frac{\sqrt{6} +\sqrt{2} }{4}$

Answer 2

To calculate the values of cos(225°-150°) and sin(225°-150°), we first need to simplify the expressions inside the trigonometric functions.

cos(225°-150°) = cos(75°)

sin(225°-150°) = sin(75°)

Now, let's evaluate these trigonometric functions using the known values:

cos(75°) is equal to approximately 0.2588.

sin(75°) is equal to approximately 0.9659.

Therefore, cos(225°-150°) is approximately 0.2588, and sin(225°-150°) is approximately 0.9659.