Question

X(x-2)(x+1)=x^2 (x-1)

Answer 1

Ответ:

Объяснение:

ось і все

Answer 2

Let's simplify the given equation step by step:

X(x - 2)(x + 1) = x^2(x - 1)

Expanding the left side:

x(x - 2)(x + 1) = x^2(x - 1)

Now, let's distribute x to the terms inside the parentheses:

(x^2 - 2x)(x + 1) = x^2(x - 1)

Next, apply the distributive property to both sides:

x^2(x + 1) - 2x(x + 1) = x^2(x - 1)

Simplifying further:

x^3 + x^2 - 2x^2 - 2x = x^3 - x^2

Combine like terms:

x^3 - x^2 - 2x^2 - 2x = x^3 - x^2

Now, let's cancel out common terms on both sides:

x^3 - 3x^2 - 2x = x^3 - x^2

Subtracting x^3 from both sides:

-3x^2 - 2x = -x^2

Adding x^2 to both sides:

-2x = 2x^2

Dividing both sides by 2:

-x = x^2

Multiplying both sides by -1 to make the coefficient positive:

x = -x^2

At this point, we have derived the equation x = -x^2 from the given equation X(x - 2)(x + 1) = x^2(x - 1). However, it's important to note that this equation is not valid for all values of x. It is a quadratic equation that only holds true for certain values of x. To find the specific values of x that satisfy this equation, you would need to solve it using standard quadratic equation-solving techniques such as factoring, completing the square, or using the quadratic formula.