Question

A/b=3,b/c=6 тогда (a^2+b^2+c^2)/ac

Answer 1

$></p> <p><img src=$

Answer 2

To find the value of (a^2 + b^2 + c^2) / ac, we need to express a, b, and c in terms of each other using the given equations.

From the equation a/b = 3, we can rearrange it to express a in terms of b as a = 3b.

Similarly, from the equation b/c = 6, we can rearrange it to express b in terms of c as b = 6c.

Substituting these expressions into the equation (a^2 + b^2 + c^2) / ac, we get:

((3b)^2 + b^2 + c^2) / (3b * c)

Simplifying further:

(9b^2 + b^2 + c^2) / (3bc)

Combining like terms:

(10b^2 + c^2) / (3bc)

Now, we can substitute the expression we derived for b in terms of c:

(10(6c)^2 + c^2) / (3(6c)c)

Simplifying further:

(360c^2 + c^2) / (18c^2)

Combining like terms:

361c^2 / 18c^2

The c^2 terms cancel out:

361 / 18

Therefore, the value of (a^2 + b^2 + c^2) / ac is 361 / 18.