Question

(2х²+3у³)(3у³-2х²)=​

Answer 1

$(2x^2+3y^3)(3y^3-2x^2)=(3y^3+2x^2)(3y^3-2x^2)=9y^6-4x^4$

Answer 2

To simplify the expression (2х²+3у³)(3у³-2х²), you can use the distributive property of multiplication over addition:

(2х² + 3у³)(3у³ - 2х²)

Now, distribute the first term (2х²) across both terms inside the second parentheses:

= 2х² * 3у³ + 2х² * (-2х²)

Next, distribute the second term (3у³) across both terms inside the second parentheses:

= 3у³ * 3у³ + 3у³ * (-2х²)

Now, simplify each term:

= 6х²у³ - 4х⁴ + 9у⁶ - 6х²у³

Finally, combine like terms:

= 6х²у³ - 6х²у³ - 4х⁴ + 9у⁶

The terms "6х²у³ - 6х²у³" cancel each other out, leaving us with the simplified expression:

= -4х⁴ + 9у⁶