Question

2(x+3)-3(2-7x)=2(x-2) 5(3x-2)=3(x+1)-2(x+2)

Answer 1

Ответ:

2х+6-6+21х=2х-4

2х+21х-2х=-4-6+6

2х и -2х взаимоуничтожаем, также как и -6 и +6

Остается:

21х=-4

х=-4:21

х=0,19

Answer 2

To solve the given equations, we will simplify them step by step. Let's start with the first equation:

1. 2(x+3) - 3(2-7x) = 2(x-2)

Expand the terms within the parentheses:

2x + 6 - 3(2) + 3(7x) = 2x - 4

Now, simplify further:

2x + 6 - 6 + 21x = 2x - 4

Combine like terms:

23x = 2x - 4

To isolate x, we want to bring all the terms containing x to one side of the equation. Let's do that:

23x - 2x = -4

Combine the x terms:

21x = -4

Finally, to find the value of x, divide both sides by 21:

x = -4/21

Now, let's move on to the second equation:

2. 5(3x-2) = 3(x+1) - 2(x+2)

Expand the terms within the parentheses:

15x - 10 = 3x + 3 - 2x - 4

Now, simplify further:

15x - 10 = x - 1

To isolate x, we want to bring all the x terms to one side of the equation:

15x - x = -1 + 10

Combine the x terms and constants:

14x = 9

Finally, to find the value of x, divide both sides by 14:

x = 9/14

So, the solutions to the given equations are:

1. x = -4/21
2. x = 9/14