Question

(х-3)^2-2х^2=3=(х+1)^2​

Answer 1

Ответ:

x1=0

x2= -3

Объяснение:

(x-3)²-2x²=3=(x+1)²

(x-2)²-2x²-3-(x+1)²=0

x²-4x-4-2x²-3-x²-2x-2=0

-2x²-6x-6=0

2x²+6x+6=0

поделим на 2

x²+3x+3=0

x²+3x=0

x(x+3)=0

1. x=0

2. x+3=0

x=-3

Answer 2

It seems there might be a typographical error in the equation you provided, as it currently contains two equal signs ("=") in a row. An equation typically has only one equal sign, indicating that both sides are equal. Let's assume that the correct equation is:

(х-3)^2 - 2х^2 = (х+1)^2

To solve this equation, we'll start by expanding the square terms and then simplifying the equation:

Step 1: Expand the squares (х-3)(х-3) - 2х^2 = (х+1)(х+1)

Step 2: Multiply the binomials (x^2 - 6x + 9) - 2x^2 = (x^2 + 2x + 1)

Step 3: Combine like terms x^2 - 6x + 9 - 2x^2 = x^2 + 2x + 1

Step 4: Move all terms to one side of the equation x^2 - 2x^2 - x^2 - 6x + 2x + 9 - 1 = 0

Step 5: Simplify further -2x^2 - 4x + 8 = 0

Step 6: Divide the whole equation by -2 to simplify further x^2 + 2x - 4 = 0

Now, this is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = 2, and c = -4. To solve the quadratic equation, you can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

Plugging in the values:

x = (-(2) ± √(2^2 - 4 * 1 * -4)) / 2 * 1 x = (-2 ± √(4 + 16)) / 2 x = (-2 ± √20) / 2 x = (-2 ± 2√5) / 2

Now, we can split this into two solutions:

1. x = (-2 + 2√5) / 2 x = -1 + √5

2. x = (-2 - 2√5) / 2 x = -1 - √5

So the two solutions for the given equation are x = -1 + √5 and x = -1 - √5.