Question

A)f(x)=3x+2x^2 x=1 ,b)f(x)=4x^2+x-1, x=0​

Answer 1

...........................

Answer 2

To evaluate the functions at the given values of x, simply substitute the given x-values into the functions and calculate the result. Let's do that:

A) f(x) = 3x + 2x^2

Given x = 1:

f(1) = 3(1) + 2(1)^2 f(1) = 3 + 2 f(1) = 5

So, when x = 1, f(x) equals 5.

B) f(x) = 4x^2 + x - 1

Given x = 0:

f(0) = 4(0)^2 + 0 - 1 f(0) = 0 + 0 - 1 f(0) = -1

So, when x = 0, f(x) equals -1.