Question

(8-9а)а=40+(6-3а)(6+3а)

Answer 1

(8-9а)а=40+(6-3а)(6+3а)

8a-9a²=40+36-9a²

8a=40+36

a=76/8

a=19/2

Answer 2

To solve the equation, let's first simplify the expression on the right side:

(6 - 3a)(6 + 3a)

To do this, you can use the FOIL method (First, Outer, Inner, Last):

(6 - 3a)(6 + 3a) = 6 * 6 + 6 * 3a - 3a * 6 - 3a * 3a = 36 + 18a - 18a - 9a^2 = 36 - 9a^2

Now the equation becomes:

8 - 9a * a = 40 + (36 - 9a^2)

Simplify the left side:

8 - 9a^2 = 40 + 36 - 9a^2

Now, get the terms with 'a^2' on one side and the constants on the other side:

8 - 9a^2 + 9a^2 = 40 + 36

The 'a^2' terms cancel out:

8 = 76

This is a contradiction. The equation has no valid solution. It means there are no values of 'a' that satisfy the equation, as both sides of the equation are not equal for any value of 'a'.