Question

(a-5)³+8Помогите плиз

Answer 1

Ответ:

Объяснение:

(a-5)³+2³= (a-5+2)((a-5)²-2(a-5)+4)= (a-3)(a²-10a+25-2a+10+4)= (a-3)(a²-12a+39)

Answer 2

1) Если нужно разложить на множители:

$\displaystyle \tt (a-5)^3+8=(a-5+2)((a-5)^2-(a-5)\cdot2+4)=(a-3)(a^2-10a+25-(2a-10)+4)=(a-3)(a^2-10a+25-2a+10+4)=(a-3)(a^2-12a+39)$

2) Если нужно упростить:

$\displaystyle \tt (a-5)^3+8=a^3-15a^2+75a-125+8=a^3-15a^2+75a-117$

Answer 3

Sure, I'd be happy to help you simplify the expression (a-5)³ + 8.

To simplify the expression (a-5)³, you need to cube the binomial (a-5) and then add 8 to the result. The cube of a binomial is found by multiplying it by itself twice:

(a-5)³ = (a-5) * (a-5) * (a-5)

Let's perform the multiplication to get the result:

(a-5) * (a-5) = a * a + 2 * a * (-5) + (-5) * (-5) = a² - 10a + 25

Now, multiply (a-5)³ by (a-5):

(a² - 10a + 25) * (a-5) = a² * (a-5) - 10a * (a-5) + 25 * (a-5) = a³ - 5a² - 10a² + 50a + 25a - 125 = a³ - 15a² + 75a - 125

Finally, add 8 to the result:

a³ - 15a² + 75a - 125 + 8 = a³ - 15a² + 75a - 117

So, the simplified expression is:

a³ - 15a² + 75a - 117