Question

(x+1)(x²-x+1)-x(x+3)=9

Answer 1

Ответ:

x=-4

Объяснение:

(x+1)(x в квадрате-x+1) это формула x в кубе и 1 в кубе

-x(x+3)=-x в квадрате-3x

x в кубе+1-x в квадрате-3x=9

x в кубе-x в квадрате-3x=8

x-3x=8

-2x=8

x=8:(-2)

x=-4

Answer 2

Let's solve the equation step by step:

Expanding the left side of the equation, we have:

(x + 1)(x² - x + 1) - x(x + 3) = 9

(x + 1)(x²) + (x + 1)(-x) + (x + 1)(1) - (x²)(x) - (x²)(3) = 9

x³ + x² - x² - x + x + 1 - x³ - 3x² = 9

Simplifying further, we get:

1 - 3x² = 9

Subtracting 1 from both sides:

-3x² = 8

Dividing both sides by -3:

x² = -8/3

Now, taking the square root of both sides (considering both positive and negative roots):

x = ±√(-8/3)

The square root of a negative number is not a real number, so there are no real solutions to this equation.