Question

А)0х-2у=6 б)3х+0у=9​

Answer 1

а) 0x - 2y = 6

0x сокращается, так как перед x множитель 0. остается

- 2y = 6

y = 6 / -2

y = - 3

б) 3x + 0y = 9

0y сокращается, т.к. перед y множитель 0. остается

3x = 9

x = 3

Answer 2

To solve the system of equations, we can use the method of substitution or elimination. However, in this case, both equations are already in a simple form and do not require any further manipulation.

Let's consider the equations:

A) 0x - 2y = 6 B) 3x + 0y = 9

In equation B, since there is no variable with 'y', we can directly solve for 'x':

3x = 9

Now, we can find the value of 'x':

x = 9 / 3 x = 3

Now that we have the value of 'x', we can substitute it back into either equation A or B to solve for 'y'. Let's use equation A:

0x - 2y = 6

Replace 'x' with its value (x = 3):

0(3) - 2y = 6

Now, isolate 'y':

-2y = 6

Divide both sides by -2:

y = 6 / -2 y = -3

So, the solution to the system of equations is x = 3 and y = -3.