Question

862а) х + 4 =0; б)x-2=12; в)x-1+7=3​

Answer 1

Ответ:

Б) х-12=12

Х=12+12

Х=24

В) х-1+7=3

Х=3-7+1

Х=-3

Answer 2

а) x+4=0

x=-4

б) х-2=12

х=12+2

х=14

в) х-1+7=3

х=3+1-7

х=4-7

х=-3

Answer 3

To solve these equations, I'll find the values of 'x' that satisfy each equation:

а) х + 4 = 0: To solve for 'x,' we need to isolate it on one side of the equation. Subtract 4 from both sides: х = -4

б) x - 2 = 12: Again, to find 'x,' we isolate it on one side. Add 2 to both sides: x = 12 + 2 x = 14

в) x - 1 + 7 = 3: First, combine like terms on the left side of the equation: x + 6 = 3

Now, isolate 'x' by subtracting 6 from both sides: x = 3 - 6 x = -3

So, the solutions for each equation are: а) х = -4 б) x = 14 в) x = -3