Question

Найти (3+2i)(-1+2i)-(7-3i)​

Answer 1

Ответ:

$-14+7i$

Объяснение:

$(3+2i)(-1+2i)-(7-3i)=-3+6i-2i-4-7+3i=-14+7i$

Answer 2

To find the result of the expression (3+2i)(-1+2i)-(7-3i), you need to follow the rules of complex number multiplication and subtraction. Here's how you can do it step-by-step:

Step 1: Multiply (3+2i) and (-1+2i): (3+2i)(-1+2i) = 3*(-1) + 32i + 2i(-1) + 2i*2i = -3 + 6i - 2i + 4i^2 = -3 + 4i + 4i^2

Step 2: Simplify 4i^2: Since i^2 is defined as -1, we have: 4i^2 = 4(-1) = -4

So, the expression becomes: -3 + 4i - 4

Step 3: Subtract (7-3i): Now, subtract (7-3i) from the result of the previous step: (-3 + 4i - 4) - (7 - 3i)

Step 4: Combine like terms: Combine the real and imaginary parts separately: Real part: -3 - 4 = -7 Imaginary part: 4i - (-3i) = 4i + 3i = 7i

So, the final result is: -7 + 7i