Question

A)(n-2)^2-(3n+1)^2b)​

Answer 1

(n-2)^2-(3n+1)^2=(н-2-3н-1)*(н-2+3н+1)=(-2н-3)*(4н-1)

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Answer 2

To simplify the given expression:

a) (n-2)^2 - (3n+1)^2

Let's expand the squared terms first: (n-2)^2 = (n-2)(n-2) = n^2 - 4n + 4 (3n+1)^2 = (3n+1)(3n+1) = 9n^2 + 6n + 1

Now, substitute the expanded forms back into the original expression: (n-2)^2 - (3n+1)^2 = (n^2 - 4n + 4) - (9n^2 + 6n + 1)

Next, distribute the negative sign to the terms inside the second parentheses: (n^2 - 4n + 4) - (9n^2 + 6n + 1) = n^2 - 4n + 4 - 9n^2 - 6n - 1

Now, combine like terms: n^2 - 9n^2 = -8n^2 -4n - 6n = -10n 4 - 1 = 3

The simplified expression is: a) -8n^2 - 10n + 3

b) The expression is not given. Please provide the expression to simplify, and I'd be happy to help!