Question

F(x)=x^3+27 в точке x0=-3

Answer 1

Ответ:

f(x) = x^3 + 27 ;

f ' (x) = 3x^2 ;

f(-3) = 3*(-3)^2 = 3*9 = 27

Объяснение:

Answer 2

To find the value of the function $F(x)=x^3+27$ at the point $x_0=-3$, we simply need to substitute $x_0$ into the function and calculate the result.

So, let's do that:

$F(-3) = (-3)^3 + 27$

Now, perform the calculations:

$F(-3) = -27 + 27 = 0$

Therefore, $F(x_0) = 0$ when $x_0 = -3$.