Question

Как решить эту задачу? При каких значениях a система неравенств не имеет решений? {5x>15 {x< или = a Смотреть ответ sergeevaolga5 sergeevaolga5 Ответ: при а=3 Объяснение: Данная система уравнений не имеет решений в случае, когда неравенства несовместные (т.е. неравенства, не имеющих общих решений): Первое неравtнство  5х>15                                       x>3 имеет решения при  x∈(3;+∞) Второе неравенство  x≤ a будет несовместным с первым, при x∈(-∞;3]. Получаем несовместную систему: {x>3 {x≤3 Итак, при а=3 данная система неравенств не имеет решений. Новые вопросы в Алгебра как найти наибольшее или наименьшее значение многочлена или выражения? у класс! сроооооооооооооооооооооооооооооооооооооооочноооооооооооо! помогите срочно пожалуйста ​ СРОЧНО!!! Приведите выражение к многочлену стандартного вида, используя формулы сокращённого умножения:(1/2m+4n)^2 5. Подайте тричлен у чигляді У зигляді квадрата двочлена: квадрата двочлена: а² + 8 +16.​ ДУЖЕ ТЕРМІНОВО! 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Answer 1

Для начала, давайте разберёмся с решением данной системы неравенств. У вас есть два неравенства:

1. $5x > 15$
2. $x \leq a$

Первое неравенство можно переписать в виде $x > 3$, так как $5x > 15$ означает, что $x$ должно быть больше 3.

Второе неравенство $x \leq a$ означает, что $x$ не должно превышать $a$.

Таким образом, система неравенств имеет решение, когда $x > 3$ и $x \leq a$, то есть при условии $3 < x \leq a$.

Теперь перейдём к вопросу о нахождении наибольшего или наименьшего значения многочлена или выражения. Для этого давайте рассмотрим выражение $(1/2m + 4n)^2$.

Для упрощения выражения можно воспользоваться формулой квадрата суммы:

$(a + b)^2 = a^2 + 2ab + b^2$

В данном случае, $a = \frac{1}{2m}$ и $b = 4n$. Подставляя значения, получаем:

$(\frac{1}{2m} + 4n)^2 = (\frac{1}{2m})^2 + 2 \cdot (\frac{1}{2m}) \cdot (4n) + (4n)^2$

Упростим каждое слагаемое:

$(\frac{1}{4m^2} + \frac{4n}{m} + 16n^2)$

Таким образом, выражение $(1/2m + 4n)^2$ может быть приведено к многочлену стандартного вида $\frac{1}{4m^2} + \frac{4n}{m} + 16n^2$.

Если у вас возникнут дополнительные вопросы, не стесняйтесь спрашивать!