Question

-c(c+3)+(c+4)² при c=-2/5

Answer 1

Ответ:

14

Объяснение:

-c(c+3)+(c+4)^2=(-c)^2-3c+c^2+8c+16

-(2/5)^2-3*(-2/5)+(-2/5)^2+8*(-2/5)+16=6/5-16/5+16=6-16+80/5=14

Answer 2

To evaluate the expression -c(c+3)+(c+4)² when c = -2/5, we can substitute the value of c into the expression and simplify it step by step.

First, let's substitute c = -2/5 into the expression:

-(-2/5)(-2/5 + 3) + (-2/5 + 4)²

Next, simplify the terms inside the parentheses:

= (2/5)(-2/5 + 15/5) + (-2/5 + 4)²

= (2/5)(13/5) + (18/5)²

Now, multiply the fractions:

= 26/25 + (324/25)

To add these fractions, we need a common denominator, which is 25:

= (26 + 324)/25

= 350/25

Finally, simplify the fraction:

= 14

Therefore, when c = -2/5, the value of the expression -c(c+3)+(c+4)² is 14.