Question

1) 2х-3-12=6 2) -4х+6=12 3) х+3+х-3=6

Answer 1

Ответ:

2х-3-12=6

2х=6+3+12

2х=21

х=21:2

х=10,5

-4х+6=12

-4х=12-6

-4х=6

х=-1,5

х+3+х-3=6

х+х+3-3=6

2х+0=6

2х=6-0

2х=6

х=6:2

х=3

Answer 2

To solve these equations, we'll isolate the variable (x) on one side of the equation. Here's how to do it step by step:

1. 2x - 3 - 12 = 6

Step 1: Combine like terms on the left side of the equation. 2x - 15 = 6

Step 2: Move the constant term (-15) to the right side by adding 15 to both sides of the equation. 2x = 6 + 15 2x = 21

Step 3: Isolate x by dividing both sides by the coefficient of x, which is 2. x = 21 / 2 x = 10.5

So, the solution for the first equation is x = 10.5.

2. -4x + 6 = 12

Step 1: Move the constant term (6) to the right side by subtracting 6 from both sides of the equation. -4x = 12 - 6 -4x = 6

Step 2: Isolate x by dividing both sides by the coefficient of x, which is -4. x = 6 / -4 x = -1.5

So, the solution for the second equation is x = -1.5.

3. x + 3 + x - 3 = 6

Step 1: Combine like terms on the left side of the equation. 2x = 6

Step 2: Isolate x by dividing both sides by the coefficient of x, which is 2. x = 6 / 2 x = 3

So, the solution for the third equation is x = 3.

Final solutions:

1. x = 10.5
2. x = -1.5
3. x = 3