Question

Log0,7 (4-6x) - log 0,7 (4-2x) => log0,7 2

Answer 1

Ответ:

Объяснение:

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Answer 2

To solve this logarithmic equation, we can use the properties of logarithms. One of the properties states that the difference of logarithms with the same base is the logarithm of the quotient of the numbers being logged.

So, let's apply that property to your equation:

log₀.₇(4 - 6x) - log₀.₇(4 - 2x) = log₀.₇(2)

Now, we can simplify the left side using the quotient rule of logarithms:

log₀.₇((4 - 6x) / (4 - 2x)) = log₀.₇(2)

Now, we have the equation:

(4 - 6x) / (4 - 2x) = 2

Now, we can solve for x. Start by cross-multiplying:

4 - 6x = 2(4 - 2x)

Distribute the 2 on the right side:

4 - 6x = 8 - 4x

Now, isolate the variable x:

-6x + 4x = 8 - 4

-2x = 4

x = -2

So, the solution to the equation is x = -2.