Question

1) 4х+у=12, 2) 6х-у=9, 3) х+у=10, 4) 2х-3у=21,

Answer 1

задание сдесь какое ? x и y найти ?

Answer 2

To solve this system of equations, we can use various methods such as substitution, elimination, or matrix methods. Let's solve it using the substitution method.

Given the system of equations:

1. 4x + y = 12
2. 6x - y = 9
3. x + y = 10
4. 2x - 3y = 21

We'll start by solving equations 1) and 3) simultaneously:

From equation 3), we have: x + y = 10 Solving for x, we get: x = 10 - y

Substituting x = 10 - y into equation 1), we get: 4(10 - y) + y = 12 40 - 4y + y = 12 40 - 3y = 12 -3y = 12 - 40 -3y = -28 y = -28 / -3 y = 28 / 3

Now that we have the value of y, we can substitute it back into equation 3) to find x: x + (28 / 3) = 10 x = 10 - 28 / 3 x = 30 / 3 - 28 / 3 x = (30 - 28) / 3 x = 2 / 3

So the solution to the system of equations is x = 2/3 and y = 28/3.