Question

-x²+8x=74x²+5x+1=0.. ​

Answer 1

ОТВЕТ ВО ВЛОЖЕНИИИИиииии

Answer 2

It looks like you have a system of two quadratic equations. To solve this system, we can use the quadratic formula. The quadratic formula is given by:

For a quadratic equation ax² + bx + c = 0, the solutions are: x = (-b ± √(b² - 4ac)) / 2a

Let's solve each equation separately using the quadratic formula:

1. -x² + 8x = 7 This equation can be rearranged to the standard quadratic form: -x² + 8x - 7 = 0 Here, a = -1, b = 8, and c = -7.

   Plugging these values into the quadratic formula: x = (-8 ± √(8² - 4(-1)(-7))) / (2(-1)) x = (-8 ± √(64 - 28)) / -2 x = (-8 ± √36) / -2 x = (-8 ± 6) / -2

   So, the solutions are: x = (-8 + 6) / -2 = -2 / -2 = 1 x = (-8 - 6) / -2 = -14 / -2 = 7

2. 74x² + 5x + 1 = 0 Here, a = 74, b = 5, and c = 1.

   Plugging these values into the quadratic formula: x = (-5 ± √(5² - 4(74)(1))) / (2(74)) x = (-5 ± √(25 - 296)) / 148 x = (-5 ± √(-271)) / 148

   Since the discriminant (b² - 4ac) is negative, the solutions will involve complex numbers.

   x = (-5 ± √271)i / 148

Therefore, the solutions to the first equation are x = 1 and x = 7, and the solutions to the second equation involve complex numbers: x = (-5 + √271)i / 148 and x = (-5 - √271)i / 148.