Question

2cos(3a+b)×s8n(3a-b)=?

Answer 1

Ответ:

16ns×cos(3a+b)×(3a-b)

Объяснение:

1) Умножаем:2×8=16

2)Получаем:16cos(3a+b)×sn×(3a-b)

3) Поменять порядок слагаемых или множителей.

4)Получаем ответ.

Answer 2

It seems like you have provided an equation involving trigonometric functions, but there might be a typo in the equation. It looks like you intended to write "sin" instead of "s8n". Assuming this correction, the equation would be:

$2\cos(3a+b) \cdot \sin(3a-b)$

If you would like me to simplify this expression or provide any further information, please let me know.