Question

8а^3-1/а^4+6а^2÷2а^2-а/а^2+6

Answer 1

Ответ:

Ответ и объяснение на рисунке

Answer 2

It looks like you've provided a mathematical expression. I'll help you simplify it step by step:

The expression is:

(8a^3 - 1) / (a^4 + 6a^2) ÷ (2a^2 - a) / (a^2 + 6)

Let's simplify it step by step:

1. Combine the numerators and denominators of both fractions: Numerator: 8a^3 - 1 Denominator: a^4 + 6a^2

   Numerator: 2a^2 - a Denominator: a^2 + 6

2. Divide the first fraction by the second fraction (invert and multiply): (8a^3 - 1) / (a^4 + 6a^2) * (a^2 + 6) / (2a^2 - a)

3. Factor the numerator of the first fraction (difference of cubes): 8a^3 - 1 = (2a - 1)(4a^2 + 2a + 1)

4. Factor the denominator of the first fraction and the denominator of the second fraction: a^4 + 6a^2 = a^2(a^2 + 6) 2a^2 - a = a(2a - 1)

5. Substitute the factored forms back into the expression: ((2a - 1)(4a^2 + 2a + 1)) / (a^2(a^2 + 6)) * (a^2 + 6) / (a(2a - 1))

6. Simplify by canceling out common factors: (4a^2 + 2a + 1) / a^2

So, the simplified expression is: (4a^2 + 2a + 1) / a^2