Question

(x+3)4-26(x+3)2+25=0

Answer 1

Ответ:

На фотке решение

Объяснение:

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Answer 2

To solve the quadratic equation given, let's substitute a variable to simplify the equation:

Let's substitute (x+3) with 'u'. Then the equation becomes:

u^4 - 26u^2 + 25 = 0

Now, we have a quadratic equation in terms of 'u'. Let's solve it using factoring:

(u^2 - 1)(u^2 - 25) = 0

Now we have two quadratic equations to solve:

1. u^2 - 1 = 0: Solving this equation, we get: u^2 = 1 u = ±1

2. u^2 - 25 = 0: Solving this equation, we get: u^2 = 25 u = ±5

Since u = x + 3, we substitute back to find the values of x:

1. If u = 1: x + 3 = 1 x = -2

2. If u = -1: x + 3 = -1 x = -4

3. If u = 5: x + 3 = 5 x = 2

4. If u = -5: x + 3 = -5 x = -8

Therefore, the solutions to the given equation are x = -2, -4, 2, and -8.