Question

-3y(-y-2)-(y-2)(y+8)-20

Answer 1

Ответ:

2y (в квадратке) -4

Объяснение:

Answer 2

Ответ:

-3y(-y-2)-(y-2)(y+8)-20=3у²+6у-(у²+8у-2у-16)-20=3у²+6у-(у²+6у-16) -20=3у²+6у-у²-6у+16-20=2у²-4

Answer 3

Let's simplify the expression step by step:

-3y(-y-2) - (y-2)(y+8) - 20

First, distribute -3y to both terms inside the first parentheses:

3y^2 + 6y - (y-2)(y+8) - 20

Next, expand the second term using the distributive property:

3y^2 + 6y - (y^2 + 8y - 2y - 16) - 20

Combine like terms within the parentheses:

3y^2 + 6y - (y^2 + 6y - 16) - 20

Now distribute the negative sign to each term inside the parentheses:

3y^2 + 6y - y^2 - 6y + 16 - 20

Simplify the terms:

2y^2 + 16 - 20

Combine constants:

2y^2 - 4

So, the simplified expression is:

2y^2 - 4