Question

(7b+...)(7b−...) = 49b2−36.

Answer 1

Ответ:

$(7d +6)(7b -6)$

Answer 2

It looks like you've provided an equation in the form of a quadratic expression multiplied by its conjugate. The general form of such an expression is:

$(a + b)(a - b) = a^2 - b^2$

In your case, you have:

$(7b + \ldots)(7b - \ldots) = 49b^2 - 36$

To solve this, you need to find the missing terms in the parentheses. To match the pattern, you can express $49b^2 - 36$ as the difference of squares:

$49b^2 - 36 = (7b)^2 - 6^2$

Now the equation matches the difference of squares form: $a^2 - b^2$. So, you can rewrite it as:

$(7b + 6)(7b - 6) = 49b^2 - 36$

Therefore, the missing terms in the parentheses are $+6$ and $-6$, and the equation is balanced.