Question

1) √10+3x=√14-x 2) √x-2=x-4

Answer 1

Ответ:

Объяснение:

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x=(9±3)/2= 6;3

3 не подходит по одз!!

Ответ ;  6

Answer 2

It looks like you've provided two equations involving square roots and variables. You're looking to solve for the values of 'x' that satisfy these equations. Let's solve them step by step:

Equation 1: √10 + 3x = √14 - x

Step 1: Isolate the square root terms on one side and the variable terms on the other side.

Start by adding 'x' to both sides:

√10 + 3x + x = √14

Simplify the left side:

4x + √10 = √14

Step 2: Subtract √10 from both sides:

4x = √14 - √10

Step 3: Divide both sides by 4:

x = (1/4) * (√14 - √10)

This is the solution for 'x' in terms of square roots.

Equation 2: √x - 2 = x - 4

Step 1: Isolate the square root term and the variable term on opposite sides.

Start by adding 2 to both sides:

√x = x - 2 + 4

Simplify the right side:

√x = x + 2

Step 2: Square both sides to eliminate the square root:

x = (x + 2)^2

Step 3: Expand the right side:

x = x^2 + 4x + 4

Step 4: Rearrange to form a quadratic equation:

x^2 + 3x + 4 = 0

This is a quadratic equation. You can solve it using the quadratic formula or factoring. The quadratic formula gives:

x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 1, b = 3, and c = 4. Plugging these values in:

x = (-3 ± √(3^2 - 4 * 1 * 4)) / (2 * 1) x = (-3 ± √(9 - 16)) / 2 x = (-3 ± √(-7)) / 2

Since the square root of a negative number results in an imaginary number, the solutions will be complex:

x = (-3 + √7i) / 2 and x = (-3 - √7i) / 2

These are the complex solutions for 'x' in the second equation.

Keep in mind that these solutions involve imaginary numbers, which might not have real-world interpretations depending on the context of your problem.