Question

1)9x^2>0 2)x^2-10x =0

Answer 1

1) 9x² > 0

x² > 0

Ответ : x ∈ (- ∞ ; 0) ∪ ( ; + ∞)

2) x² - 10x = 0

x(x - 10) =0

или   x₁ = 0

или   x - 10 = 0    и тогда   x₂ = 10

Ответ : 0 ; 10

Answer 2

Ответ:

1) 9x²>0

9x²=0

x ∈ (-∞; 0) u (0; +∞)

2) x^2-10x =0

x(x-10)=0

x=0; x-10=0

x=0; x=10

Answer 3

Let's analyze the given inequalities and equation:

1. $9x^2 > 0$:

This inequality states that $9x^2$ is greater than 0. Since $9x^2$ is always non-negative (it's the square of a real number), the only way for it to be greater than 0 is if $x$ is not equal to 0. In other words, the solution to this inequality is all real numbers except $x = 0$.

2. $x^2 - 10x = 0$:

This equation is a quadratic equation, and you want to find the values of $x$ that satisfy it. To solve it, you can factor out $x$ from the left-hand side:

$x(x - 10) = 0$

Now, you have a product equal to 0. According to the zero-product property, one or both of the factors must be equal to 0:

$x = 0$ or $x - 10 = 0$

Solving the second equation:

$x - 10 = 0$
$x = 10$

So, the solutions to the equation are $x = 0$ and $x = 10$.

In summary:

• For the inequality $9x^2 > 0$, the solution is all real numbers except $x = 0$.
• For the equation $x^2 - 10x = 0$, the solutions are $x = 0$ and $x = 10$.