Question

5x+ 2y =-14 10x + 3y =- 21

Answer 1

$\left \{ {{5x+2y=-14}|*(-2) \atop {10x+3y=-21}} \right.\\\\+\left \{ {{-10x-4y=28} \atop {10x+3y=-21}} \right.\\ --------\\-y=7\\\\y=-7\\\\5x=-2y-14=-2*(-7)-14=14-14=0\\\\x=0\\\\Otvet:\boxed{(0;-7)}$

Answer 2

Ответ:

(0; -7)

Объяснение:

$\left \{ {{5x + 2y = -14 | \cdot (-2)} \atop {10x + 3y = -21}} \right.\\\\\left \{ {{-10x - 4y = 28} \atop {10x + 3y = -21}} \right.\\\\\left \{ {{-10x - 4y = 28} \atop {-y = 7}} \right.\\\\\left \{ {{-10x - 4y = 28} \atop {y = -7}} \right.\\\\\left \{ {{x = 0} \atop {y = -7}} \right.$

Answer 3

To solve the system of equations:

Equation 1: 5x + 2y = -14 Equation 2: 10x + 3y = -21

There are multiple methods to solve this system, such as substitution, elimination, or matrix methods. Here, I'll demonstrate the elimination method:

To eliminate one of the variables, we can multiply Equation 1 by -3 and Equation 2 by 2, then add the equations together:

-3 * (5x + 2y) = -3 * (-14) 2 * (10x + 3y) = 2 * (-21)

Simplifying these equations gives:

-15x - 6y = 42 20x + 6y = -42

Now, we can add the equations:

(-15x - 6y) + (20x + 6y) = 42 + (-42)

This simplifies to:

5x = 0

Dividing both sides by 5, we find:

x = 0

To find the value of y, substitute the value of x into one of the original equations, let's use Equation 1:

5(0) + 2y = -14 2y = -14 y = -14/2 y = -7

Therefore, the solution to the system of equations is x = 0 and y = -7.