Question

1/7×(21x-14)+3/7×(7x+21) при x=6,05​

Answer 1

1/7×(21x-14)+3/7×(7x+21) при x=6,05​

Ответ:

43,3

Объяснение:

21x/7 -14/7 + 3×7x/7 + 21×3/7=3x-2+3x+9=6x+7

6x+7=6×6.05+7=43,3

Answer 2

To find the value of the expression 1/7 × (21x - 14) + 3/7 × (7x + 21) when x = 6.05, we substitute the value of x into the expression and perform the calculations. Let's do that:

1/7 × (21x - 14) + 3/7 × (7x + 21) = 1/7 × (21(6.05) - 14) + 3/7 × (7(6.05) + 21) = 1/7 × (126.05 - 14) + 3/7 × (42.35 + 21) = 1/7 × (112.05) + 3/7 × (63.35) = 16.007142857142856 + 27.007142857142856 = 43.01428571428571

Therefore, when x = 6.05, the value of the expression 1/7 × (21x - 14) + 3/7 × (7x + 21) is approximately 43.014.