Question

1)5x+2y =15,8x + 3y = 20;​

Answer 1

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Answer 2

To solve the system of equations:

1. 5x + 2y = 15
2. 8x + 3y = 20

There are multiple methods you can use to solve this system, such as substitution or elimination. I'll demonstrate how to solve it using the elimination method.

To eliminate one variable, we'll multiply the first equation by 3 and the second equation by 2. This will create a cancellation when we add the equations together.

3 * (5x + 2y) = 3 * 15 2 * (8x + 3y) = 2 * 20

Simplifying the equations:

15x + 6y = 45 16x + 6y = 40

Now, subtracting the second equation from the first equation:

(15x + 6y) - (16x + 6y) = 45 - 40

This simplifies to:

15x + 6y - 16x - 6y = 5

Combining like terms:

15x - 16x + 6y - 6y = 5

-x = 5

To solve for x, multiply both sides by -1:

x = -5

Now, substitute the value of x back into one of the original equations. Let's use the first equation:

5x + 2y = 15

Substituting x = -5:

5(-5) + 2y = 15

-25 + 2y = 15

2y = 15 + 25

2y = 40

Divide both sides by 2 to solve for y:

y = 40/2

y = 20

Therefore, the solution to the system of equations is x = -5 and y = 20.