Question

2(x+1)²-(x-3)(x+3)=7+x²​

Answer 1

Ответ:

Объяснение:

Слишком коротко. Напишите минимум 20 символов, чтобы объяснить все.

Answer 2

To solve this equation, we'll start by expanding and simplifying both sides, and then we'll solve for the variable $x$:

Given equation: $2(x+1)^2 - (x-3)(x+3) = 7 + x^2$

Let's simplify step by step:

1. Expand $(x+1)^2$ and $(x-3)(x+3)$: $2(x^2 + 2x + 1) - (x^2 - 9) = 7 + x^2$

2. Distribute $2$ through $x^2 + 2x + 1$: $2x^2 + 4x + 2 - (x^2 - 9) = 7 + x^2$

3. Distribute $-1$ through $-x^2$ and $9$: $2x^2 + 4x + 2 - x^2 + 9 = 7 + x^2$

4. Combine like terms on the left side: $x^2 + 4x + 11 = 7 + x^2$

5. Subtract $x^2$ from both sides to eliminate the $x^2$ terms: $4x + 11 = 7$

6. Subtract $11$ from both sides: $4x = -4$

7. Divide both sides by $4$: $x = -1$

So, the solution to the equation is $x = -1$.