Question

(2x-1)(4x²+2x+1)-(2x+5)(4x²-7)=41+x²​

Answer 1

Ответ:

Объяснение:

(2x-1)(4x²+2x+1)-(2x+5)(4x²-7)=41+x²​

8x³+4x²+2x-4x²-2x- 1 -8x³+14x-20x²+35-41-x² = 0  - (перемножил скобки друг на друга и перенёс 41+х² в левую часть с другими знаками)

-1+14х-20х²+35-41-х²=0 (сократил числа с разными знаками)

-21х²+14х-7=0/(-7)

3х²-2х+1=0

Д= 4-12= -8 <0  - нет корней

Answer 2

Вот так должно вроде

Answer 3

Let's solve this equation step by step:

Given expression: (2x - 1)(4x² + 2x + 1) - (2x + 5)(4x² - 7) = 41 + x²

Expand the expressions within the parentheses:

(2x)(4x²) + (2x)(2x) + (2x)(1) - (1)(4x²) - (1)(2x) - (1)(1) - (2x)(4x²) + (2x)(7) + (5)(4x²) - (5)(-7) = 41 + x²

Simplify the terms:

8x³ + 4x³ + 2x - 4x² - 2x - 1 - 8x³ + 14x² + 20x² + 35 = 41 + x²

Combine like terms:

12x³ + 12x² + 2x + 34 = 41 + x²

Move all terms to one side of the equation:

12x³ + 11x² + 2x - 7 = 0

Now, this is a cubic equation in terms of x. While it can be solved, finding the exact solutions can be complex depending on the specific coefficients. You might use numerical methods or software to approximate the solutions. If you're looking for numerical solutions, you can use tools like graphing calculators or computational software.