Question

3x-y+10=05x+3y+26=0​

Answer 1

Ответ

1)-1; 2)-7

Правильно

Answer 2

1)3x-y+10=0
3х-у=-10
3х=у-10
Ху=3:10
Ху=0,3

Answer 3

To solve the system of equations:

3x - y + 10 = 0 ...(Equation 1) 5x + 3y + 26 = 0 ...(Equation 2)

We can use the method of substitution or elimination. Let's solve it using the method of elimination.

First, let's multiply Equation 1 by 3 and Equation 2 by -1 to make the coefficients of y opposite:

3(3x - y + 10) = 3(0) -1(5x + 3y + 26) = -1(0)

Simplifying these equations, we get:

9x - 3y + 30 = 0 ...(Equation 3) -5x - 3y - 26 = 0 ...(Equation 4)

Now, let's add Equation 3 and Equation 4 to eliminate the y term:

(9x - 3y + 30) + (-5x - 3y - 26) = 0 + 0

Combining like terms, we have:

9x - 5x - 3y - 3y + 30 - 26 = 0

4x - 6y + 4 = 0

Simplifying further:

4x - 6y = -4 ...(Equation 5)

Now we have two equations:

4x - 6y = -4 ...(Equation 5) 5x + 3y + 26 = 0 ...(Equation 2)

To eliminate the y term, let's multiply Equation 5 by 3 and Equation 2 by 2:

3(4x - 6y) = 3(-4) 2(5x + 3y + 26) = 2(0)

Simplifying these equations, we get:

12x - 18y = -12 ...(Equation 6) 10x + 6y + 52 = 0 ...(Equation 7)

Now, let's add Equation 6 and Equation 7 to eliminate the y term:

(12x - 18y) + (10x + 6y + 52) = -12 + 0

Combining like terms, we have:

12x + 10x - 18y + 6y + 52 - 12 = 0

22x - 12y + 40 = 0

Simplifying further:

22x - 12y = -40 ...(Equation 8)

Now we have two equations:

22x - 12y = -40 ...(Equation 8) 5x + 3y + 26 = 0 ...(Equation 2)

To eliminate the y term, let's multiply Equation 8 by 3 and Equation 2 by 4:

3(22x - 12y) = 3(-40) 4(5x + 3y + 26) = 4(0)

Simplifying these equations, we get:

66x - 36y = -120 ...(Equation 9) 20x + 12y + 104 = 0 ...(Equation 10)

Now, let's add Equation 9 and Equation 10 to eliminate the y term:

(66x - 36y) + (20x + 12y + 104) = -120 + 0

Combining like terms, we have:

66x + 20x - 36y + 12y + 104 - 120 = 0

86x - 24y - 16 =