Question

1) 5(x+4)<2(4x-5)2) 2-3(x-5)>5(1-x)​

Answer 1

Держите удачи всем....

Answer 2

Sure, I can help you solve these inequalities. Let's solve them step by step:

Inequality 1: $5(x+4) < 2(4x-5)$

First, distribute the values inside the parentheses:

$5x + 20 < 8x - 10$

Now, subtract $5x$ from both sides:

$20 < 3x - 10$

Add $10$ to both sides:

$30 < 3x$

Finally, divide both sides by $3$:

$10 < x$

So, the solution for the first inequality is $x > 10$.

Inequality 2: $2 - 3(x-5) > 5(1-x)$

Distribute the values inside the parentheses:

$2 - 3x + 15 > 5 - 5x$

Combine like terms:

$17 - 3x > 5 - 5x$

Add $3x$ to both sides:

$17 > 5 - 2x$

Subtract $5$ from both sides:

$12 > -2x$

Divide both sides by $-2$ (remember to reverse the inequality when dividing by a negative number):

$-6 < x$

So, the solution for the second inequality is $x > -6$.

To summarize:

1. The solution for the first inequality is $x > 10$.
2. The solution for the second inequality is $x > -6$.