Question

(2x-3)(2x+3)-(x-4)^2=3x(x+6)+5

Answer 1

Ответ:

.....................................

Answer 2

сразу видим формула разности квадратов и квадрата разности.

x² - y² = (x - y)(x + y)

(x - y)² = x² - 2xy + y²

4x² - 9 - x² + 8x - 16 = 3x² + 18x + 5

3x² - 3x² - 25 - 5 = 18x - 8x

-30 = 10x

x = -3

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Answer 3

Let's simplify the given equation step by step:

(2x - 3)(2x + 3) - (x - 4)^2 = 3x(x + 6) + 5

Expanding the expressions on both sides:

(4x^2 - 9) - (x^2 - 8x + 16) = 3x^2 + 18x + 5

Simplifying further:

4x^2 - 9 - x^2 + 8x - 16 = 3x^2 + 18x + 5

Combine like terms:

3x^2 + 8x - 25 = 3x^2 + 18x + 5

Subtracting 3x^2 from both sides:

8x - 25 = 18x + 5

Subtracting 8x from both sides:

-25 = 10x + 5

Subtracting 5 from both sides:

-30 = 10x

Dividing both sides by 10:

-3 = x

So the solution to the given equation is x = -3.