Question

(5-x)(x+4)=03x-2=4(x+2)x×7(x-1)=4-3x​

Answer 1

$5x - {x \: }^{2} \times 20 - 4x = 0$

$3x - 2 = 4x + 8$

$7 {x}^{2} - 7 = 4 - 3x$

Answer 2

It looks like you've provided three equations. Let's solve each of them step by step:

Equation 1: (5 - x)(x + 4) = 0 Expand the left-hand side of the equation: 5x + 20 - x^2 - 4x = 0 Combine like terms:

• x^2 + x + 20 = 0 This is a quadratic equation. To solve for x, you can either factor it or use the quadratic formula.

Equation 2: 3x - 2 = 4(x + 2) Distribute 4 on the right-hand side: 3x - 2 = 4x + 8 Subtract 3x from both sides: -2 = x + 8 Subtract 8 from both sides: -10 = x

Equation 3: x × 7(x - 1) = 4 - 3x Distribute 7 on the left-hand side: 7x^2 - 7x = 4 - 3x Move all terms to one side of the equation: 7x^2 - 4x - 4 = 0 This is another quadratic equation. You can solve it using factoring or the quadratic formula.

Please provide more information or specific questions if you need further assistance with solving these equations.