Question

(x+8)(4x-1.6)=0 (1.1y-3.3)(4+5y)=0

Answer 1

Если не ошибаюсь то нужно потом умножать если не правильно то извиняюсь

Answer 2

Ответ:

В первом ответ: 0,4  и -8. Во втором ответ: 3 и -0,8.

Объяснение:

Answer 3

It looks like you've provided two equations involving polynomial expressions and set them equal to zero. To solve for the variables in each equation, we need to find the values of x and y that satisfy each equation. Let's solve each equation separately:

Equation 1: $(x + 8)(4x - 1.6) = 0$

To solve this equation, we set each factor equal to zero and solve for $x$:

1. $x + 8 = 0$ $x = -8$

2. $4x - 1.6 = 0$ $4x = 1.6$ $x = \frac{1.6}{4}$ $x = 0.4$

So, the solutions for $x$ in the first equation are $x = -8$ and $x = 0.4$.

Equation 2: $(1.1y - 3.3)(4 + 5y) = 0$

To solve this equation, we set each factor equal to zero and solve for $y$:

1. $1.1y - 3.3 = 0$ $1.1y = 3.3$ $y = \frac{3.3}{1.1}$ $y = 3$

2. $4 + 5y = 0$ $5y = -4$ $y = -\frac{4}{5}$

So, the solutions for $y$ in the second equation are $y = 3$ and $y = -\frac{4}{5}$.

In summary, for the first equation, the solutions for $x$ are $x = -8$ and $x = 0.4$. For the second equation, the solutions for $y$ are $y = 3$ and $y = -\frac{4}{5}$.