Question

X+ y =4,x2 - y2 = 8​

Answer 1

Ответ:

1) х+y=4 равно x+y-4=0

Answer 2

It looks like you have a system of two equations with two variables:

1. $x + y = 4$
2. $x^2 - y^2 = 8$

Let's solve for the variables $x$ and $y$:

First, let's solve equation (1) for one of the variables. We'll solve for $x$: $x = 4 - y$

Now, substitute this value of $x$ into equation (2): $(4 - y)^2 - y^2 = 8$

Expand and simplify the left side: $16 - 8y + y^2 - y^2 = 8$

Combine the $y^2$ terms: $16 - 8y = 8$

Subtract 16 from both sides: $-8y = -8$

Divide by -8: $y = 1$

Now that we have the value of $y$, substitute it back into the equation for $x$: $x = 4 - 1 = 3$

So, the solution to the system of equations is $x = 3$ and $y = 1$.